2(3k+21/3)-8k=9k-41/3-5k

Solution for 2(3k+21/3)-8k=9k-41/3-5k equation:

2(3k+21/3)-8k=9k-41/3-5k

We move all terms to the left:

2(3k+21/3)-8k-(9k-41/3-5k)=0


Domain of the equation: 3-5k)!=0

We move all terms containing k to the left, all other terms to the right

-5k)!=-3

k!=-3/1

k!=-3

k∈R


We add all the numbers together, and all the variables

2(3k+7)-8k-(+4k-41/3)=0

We add all the numbers together, and all the variables

-8k+2(3k+7)-(+4k-41/3)=0

We multiply parentheses

-8k+6k-(+4k-41/3)+14=0

We get rid of parentheses

-8k+6k-4k+14+41/3=0

We multiply all the terms by the denominator


-8k*3+6k*3-4k*3+41+14*3=0

We add all the numbers together, and all the variables

-8k*3+6k*3-4k*3+83=0

Wy multiply elements

-24k+18k-12k+83=0

We add all the numbers together, and all the variables

-18k+83=0

We move all terms containing k to the left, all other terms to the right

-18k=-83

k=-83/-18

k=4+11/18