2(3k+3)=4K-2k+18

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Solution for 2(3k+3)=4K-2k+18 equation: 



2(3k+3)=4-2k+18

We move all terms to the left:

2(3k+3)-(4-2k+18)=0

We add all the numbers together, and all the variables

2(3k+3)-(-2k+22)=0

We multiply parentheses

6k-(-2k+22)+6=0

We get rid of parentheses

6k+2k-22+6=0

We add all the numbers together, and all the variables

8k-16=0

We move all terms containing k to the left, all other terms to the right

8k=16

k=16/8

k=2

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