2(3k+7/3)-8k=9k-13/3-5k

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Solution for 2(3k+7/3)-8k=9k-13/3-5k equation:



2(3k+7/3)-8k=9k-13/3-5k
We move all terms to the left:
2(3k+7/3)-8k-(9k-13/3-5k)=0
Domain of the equation: 3-5k)!=0
We move all terms containing k to the left, all other terms to the right
-5k)!=-3
k!=-3/1
k!=-3
k∈R
We add all the numbers together, and all the variables
2(+3k+7/3)-8k-(+4k-13/3)=0
We add all the numbers together, and all the variables
-8k+2(+3k+7/3)-(+4k-13/3)=0
We multiply parentheses
-8k+6k-(+4k-13/3)+7/3*2=0
We get rid of parentheses
-8k+6k-4k+13/3+7/3*2=0
We calculate fractions
There is no solution for this equation

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