2(3k+7/3)-8k=9k-13/3-5k

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Solution for 2(3k+7/3)-8k=9k-13/3-5k equation: 



2(3k+7/3)-8k=9k-13/3-5k

We move all terms to the left:

2(3k+7/3)-8k-(9k-13/3-5k)=0



Domain of the equation: 3-5k)!=0

We move all terms containing k to the left, all other terms to the right

-5k)!=-3

k!=-3/1

k!=-3

k∈R



We add all the numbers together, and all the variables

2(+3k+7/3)-8k-(+4k-13/3)=0

We add all the numbers together, and all the variables

-8k+2(+3k+7/3)-(+4k-13/3)=0

We multiply parentheses

-8k+6k-(+4k-13/3)+7/3*2=0

We get rid of parentheses

-8k+6k-4k+13/3+7/3*2=0

We calculate fractions

There is no solution for this equation

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