2(3k-1)-4(k+2)=15

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Solution for 2(3k-1)-4(k+2)=15 equation: 


Simplifying
2(3k + -1) + -4(k + 2) = 15

Reorder the terms:
2(-1 + 3k) + -4(k + 2) = 15
(-1 * 2 + 3k * 2) + -4(k + 2) = 15
(-2 + 6k) + -4(k + 2) = 15

Reorder the terms:
-2 + 6k + -4(2 + k) = 15
-2 + 6k + (2 * -4 + k * -4) = 15
-2 + 6k + (-8 + -4k) = 15

Reorder the terms:
-2 + -8 + 6k + -4k = 15

Combine like terms: -2 + -8 = -10
-10 + 6k + -4k = 15

Combine like terms: 6k + -4k = 2k
-10 + 2k = 15

Solving
-10 + 2k = 15

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 2k = 15 + 10

Combine like terms: -10 + 10 = 0
0 + 2k = 15 + 10
2k = 15 + 10

Combine like terms: 15 + 10 = 25
2k = 25

Divide each side by '2'.
k = 12.5

Simplifying
k = 12.5

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