2(3k-2)-4(k+5)=

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Solution for 2(3k-2)-4(k+5)= equation:


2 (3k-2)-4 (k+5)=0

We simplify the equation to the form, which is simple to understand 
2(3k-2)-4(k+5)=0

Reorder the terms in parentheses
+(+6k-4)-4*(k+5)=0

Remove unnecessary parentheses
+6k-4-4+*(+k+5+)=0

Reorder the terms in parentheses
+6k-4+(-4k-20)=0

Remove unnecessary parentheses
+6k-4-4k-20=0

We move all terms containing k to the left and all other terms to the right. 
+6k-4k=0+4+20

We simplify left and right side of the equation. 
+2k=+24

We divide both sides of the equation by 2 to get k. 
k=12

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