2(3k-2)=k+6

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Solution for 2(3k-2)=k+6 equation: 



2(3k-2)=k+6

We move all terms to the left:

2(3k-2)-(k+6)=0

We multiply parentheses

6k-(k+6)-4=0

We get rid of parentheses

6k-k-6-4=0

We add all the numbers together, and all the variables

5k-10=0

We move all terms containing k to the left, all other terms to the right

5k=10

k=10/5

k=2

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