2(3k-5)=3(3k+4)

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Solution for 2(3k-5)=3(3k+4) equation: 



2(3k-5)=3(3k+4)

We move all terms to the left:

2(3k-5)-(3(3k+4))=0

We multiply parentheses

6k-(3(3k+4))-10=0



We calculate terms in parentheses: -(3(3k+4)), so:

3(3k+4)

We multiply parentheses

9k+12

Back to the equation:

-(9k+12)



We get rid of parentheses

6k-9k-12-10=0

We add all the numbers together, and all the variables

-3k-22=0

We move all terms containing k to the left, all other terms to the right

-3k=22

k=22/-3

k=-7+1/3

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