2(3k-6)-k+1=7-k

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Solution for 2(3k-6)-k+1=7-k equation:



2(3k-6)-k+1=7-k
We move all terms to the left:
2(3k-6)-k+1-(7-k)=0
We add all the numbers together, and all the variables
2(3k-6)-k-(-1k+7)+1=0
We add all the numbers together, and all the variables
-1k+2(3k-6)-(-1k+7)+1=0
We multiply parentheses
-1k+6k-(-1k+7)-12+1=0
We get rid of parentheses
-1k+6k+1k-7-12+1=0
We add all the numbers together, and all the variables
6k-18=0
We move all terms containing k to the left, all other terms to the right
6k=18
k=18/6
k=3

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