2(3k-8)-2=k+12

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Solution for 2(3k-8)-2=k+12 equation: 



2(3k-8)-2=k+12

We move all terms to the left:

2(3k-8)-2-(k+12)=0

We multiply parentheses

6k-(k+12)-16-2=0

We get rid of parentheses

6k-k-12-16-2=0

We add all the numbers together, and all the variables

5k-30=0

We move all terms containing k to the left, all other terms to the right

5k=30

k=30/5

k=6

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