2(3k-8)=7(k+2)

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Solution for 2(3k-8)=7(k+2) equation: 



2(3k-8)=7(k+2)

We move all terms to the left:

2(3k-8)-(7(k+2))=0

We multiply parentheses

6k-(7(k+2))-16=0



We calculate terms in parentheses: -(7(k+2)), so:

7(k+2)

We multiply parentheses

7k+14

Back to the equation:

-(7k+14)



We get rid of parentheses

6k-7k-14-16=0

We add all the numbers together, and all the variables

-1k-30=0

We move all terms containing k to the left, all other terms to the right

-k=30

k=30/-1

k=-30

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