2(3m+4)+3(m-5)=12

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Solution for 2(3m+4)+3(m-5)=12 equation: 



2(3m+4)+3(m-5)=12

We move all terms to the left:

2(3m+4)+3(m-5)-(12)=0

We multiply parentheses

6m+3m+8-15-12=0

We add all the numbers together, and all the variables

9m-19=0

We move all terms containing m to the left, all other terms to the right

9m=19

m=19/9

m=2+1/9

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