2(3m+4)+3(m-5)=12

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Solution for 2(3m+4)+3(m-5)=12 equation:



2(3m+4)+3(m-5)=12
We move all terms to the left:
2(3m+4)+3(m-5)-(12)=0
We multiply parentheses
6m+3m+8-15-12=0
We add all the numbers together, and all the variables
9m-19=0
We move all terms containing m to the left, all other terms to the right
9m=19
m=19/9
m=2+1/9

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