2(3m+4)+4(m-1)=75

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Solution for 2(3m+4)+4(m-1)=75 equation: 



2(3m+4)+4(m-1)=75

We move all terms to the left:

2(3m+4)+4(m-1)-(75)=0

We multiply parentheses

6m+4m+8-4-75=0

We add all the numbers together, and all the variables

10m-71=0

We move all terms containing m to the left, all other terms to the right

10m=71

m=71/10

m=7+1/10

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