2(3m+4)=40+2m

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Solution for 2(3m+4)=40+2m equation: 



2(3m+4)=40+2m

We move all terms to the left:

2(3m+4)-(40+2m)=0

We add all the numbers together, and all the variables

2(3m+4)-(2m+40)=0

We multiply parentheses

6m-(2m+40)+8=0

We get rid of parentheses

6m-2m-40+8=0

We add all the numbers together, and all the variables

4m-32=0

We move all terms containing m to the left, all other terms to the right

4m=32

m=32/4

m=8

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