2(3m+4m)=28

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Solution for 2(3m+4m)=28 equation: 



2(3m+4m)=28

We move all terms to the left:

2(3m+4m)-(28)=0

We add all the numbers together, and all the variables

2(+7m)-28=0

We multiply parentheses

14m-28=0

We move all terms containing m to the left, all other terms to the right

14m=28

m=28/14

m=2

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