2(3m-7)+4m=64

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Solution for 2(3m-7)+4m=64 equation: 



2(3m-7)+4m=64

We move all terms to the left:

2(3m-7)+4m-(64)=0

We add all the numbers together, and all the variables

4m+2(3m-7)-64=0

We multiply parentheses

4m+6m-14-64=0

We add all the numbers together, and all the variables

10m-78=0

We move all terms containing m to the left, all other terms to the right

10m=78

m=78/10

m=7+4/5

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