2(3m-7)-2m=10m+16

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Solution for 2(3m-7)-2m=10m+16 equation:



2(3m-7)-2m=10m+16
We move all terms to the left:
2(3m-7)-2m-(10m+16)=0
We add all the numbers together, and all the variables
-2m+2(3m-7)-(10m+16)=0
We multiply parentheses
-2m+6m-(10m+16)-14=0
We get rid of parentheses
-2m+6m-10m-16-14=0
We add all the numbers together, and all the variables
-6m-30=0
We move all terms containing m to the left, all other terms to the right
-6m=30
m=30/-6
m=-5

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