2(3n+2)+n=3n+5(6+6n)

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Solution for 2(3n+2)+n=3n+5(6+6n) equation: 



2(3n+2)+n=3n+5(6+6n)

We move all terms to the left:

2(3n+2)+n-(3n+5(6+6n))=0

We add all the numbers together, and all the variables

2(3n+2)+n-(3n+5(6n+6))=0

We add all the numbers together, and all the variables

n+2(3n+2)-(3n+5(6n+6))=0

We multiply parentheses

n+6n-(3n+5(6n+6))+4=0



We calculate terms in parentheses: -(3n+5(6n+6)), so:

3n+5(6n+6)

We multiply parentheses

3n+30n+30

We add all the numbers together, and all the variables

33n+30

Back to the equation:

-(33n+30)



We add all the numbers together, and all the variables

7n-(33n+30)+4=0

We get rid of parentheses

7n-33n-30+4=0

We add all the numbers together, and all the variables

-26n-26=0

We move all terms containing n to the left, all other terms to the right

-26n=26

n=26/-26

n=-1

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