2(3n+2)+n=3n+5(6+6n)

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Solution for 2(3n+2)+n=3n+5(6+6n) equation:



2(3n+2)+n=3n+5(6+6n)
We move all terms to the left:
2(3n+2)+n-(3n+5(6+6n))=0
We add all the numbers together, and all the variables
2(3n+2)+n-(3n+5(6n+6))=0
We add all the numbers together, and all the variables
n+2(3n+2)-(3n+5(6n+6))=0
We multiply parentheses
n+6n-(3n+5(6n+6))+4=0
We calculate terms in parentheses: -(3n+5(6n+6)), so:
3n+5(6n+6)
We multiply parentheses
3n+30n+30
We add all the numbers together, and all the variables
33n+30
Back to the equation:
-(33n+30)
We add all the numbers together, and all the variables
7n-(33n+30)+4=0
We get rid of parentheses
7n-33n-30+4=0
We add all the numbers together, and all the variables
-26n-26=0
We move all terms containing n to the left, all other terms to the right
-26n=26
n=26/-26
n=-1

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