2(3n+3)=7(3n+7)+1

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Solution for 2(3n+3)=7(3n+7)+1 equation:



2(3n+3)=7(3n+7)+1
We move all terms to the left:
2(3n+3)-(7(3n+7)+1)=0
We multiply parentheses
6n-(7(3n+7)+1)+6=0
We calculate terms in parentheses: -(7(3n+7)+1), so:
7(3n+7)+1
We multiply parentheses
21n+49+1
We add all the numbers together, and all the variables
21n+50
Back to the equation:
-(21n+50)
We get rid of parentheses
6n-21n-50+6=0
We add all the numbers together, and all the variables
-15n-44=0
We move all terms containing n to the left, all other terms to the right
-15n=44
n=44/-15
n=-2+14/15

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