2(3n+3)=7(3n+7)+1

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Solution for 2(3n+3)=7(3n+7)+1 equation: 



2(3n+3)=7(3n+7)+1

We move all terms to the left:

2(3n+3)-(7(3n+7)+1)=0

We multiply parentheses

6n-(7(3n+7)+1)+6=0



We calculate terms in parentheses: -(7(3n+7)+1), so:

7(3n+7)+1

We multiply parentheses

21n+49+1

We add all the numbers together, and all the variables

21n+50

Back to the equation:

-(21n+50)



We get rid of parentheses

6n-21n-50+6=0

We add all the numbers together, and all the variables

-15n-44=0

We move all terms containing n to the left, all other terms to the right

-15n=44

n=44/-15

n=-2+14/15

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