2(3n+3)=7(9n+3)+2

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Solution for 2(3n+3)=7(9n+3)+2 equation: 



2(3n+3)=7(9n+3)+2

We move all terms to the left:

2(3n+3)-(7(9n+3)+2)=0

We multiply parentheses

6n-(7(9n+3)+2)+6=0



We calculate terms in parentheses: -(7(9n+3)+2), so:

7(9n+3)+2

We multiply parentheses

63n+21+2

We add all the numbers together, and all the variables

63n+23

Back to the equation:

-(63n+23)



We get rid of parentheses

6n-63n-23+6=0

We add all the numbers together, and all the variables

-57n-17=0

We move all terms containing n to the left, all other terms to the right

-57n=17

n=17/-57

n=-17/57

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