2(3n+3)=7(9n+5)+4

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Solution for 2(3n+3)=7(9n+5)+4 equation: 



2(3n+3)=7(9n+5)+4

We move all terms to the left:

2(3n+3)-(7(9n+5)+4)=0

We multiply parentheses

6n-(7(9n+5)+4)+6=0



We calculate terms in parentheses: -(7(9n+5)+4), so:

7(9n+5)+4

We multiply parentheses

63n+35+4

We add all the numbers together, and all the variables

63n+39

Back to the equation:

-(63n+39)



We get rid of parentheses

6n-63n-39+6=0

We add all the numbers together, and all the variables

-57n-33=0

We move all terms containing n to the left, all other terms to the right

-57n=33

n=33/-57

n=-11/19

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