2(3n+3)=7(9n+5)+9

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Solution for 2(3n+3)=7(9n+5)+9 equation: 



2(3n+3)=7(9n+5)+9

We move all terms to the left:

2(3n+3)-(7(9n+5)+9)=0

We multiply parentheses

6n-(7(9n+5)+9)+6=0



We calculate terms in parentheses: -(7(9n+5)+9), so:

7(9n+5)+9

We multiply parentheses

63n+35+9

We add all the numbers together, and all the variables

63n+44

Back to the equation:

-(63n+44)



We get rid of parentheses

6n-63n-44+6=0

We add all the numbers together, and all the variables

-57n-38=0

We move all terms containing n to the left, all other terms to the right

-57n=38

n=38/-57

n=-2/3

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