2(3n+4)-3(n+1)=11

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Solution for 2(3n+4)-3(n+1)=11 equation: 



2(3n+4)-3(n+1)=11

We move all terms to the left:

2(3n+4)-3(n+1)-(11)=0

We multiply parentheses

6n-3n+8-3-11=0

We add all the numbers together, and all the variables

3n-6=0

We move all terms containing n to the left, all other terms to the right

3n=6

n=6/3

n=2

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