2(3n+4)=7(7n+2)+1

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Solution for 2(3n+4)=7(7n+2)+1 equation: 



2(3n+4)=7(7n+2)+1

We move all terms to the left:

2(3n+4)-(7(7n+2)+1)=0

We multiply parentheses

6n-(7(7n+2)+1)+8=0



We calculate terms in parentheses: -(7(7n+2)+1), so:

7(7n+2)+1

We multiply parentheses

49n+14+1

We add all the numbers together, and all the variables

49n+15

Back to the equation:

-(49n+15)



We get rid of parentheses

6n-49n-15+8=0

We add all the numbers together, and all the variables

-43n-7=0

We move all terms containing n to the left, all other terms to the right

-43n=7

n=7/-43

n=-7/43

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