2(3n-1)+4(n+5)=58

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Solution for 2(3n-1)+4(n+5)=58 equation: 



2(3n-1)+4(n+5)=58

We move all terms to the left:

2(3n-1)+4(n+5)-(58)=0

We multiply parentheses

6n+4n-2+20-58=0

We add all the numbers together, and all the variables

10n-40=0

We move all terms containing n to the left, all other terms to the right

10n=40

n=40/10

n=4

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