2(3n-10)=4(n-5)+2n

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Solution for 2(3n-10)=4(n-5)+2n equation: 



2(3n-10)=4(n-5)+2n

We move all terms to the left:

2(3n-10)-(4(n-5)+2n)=0

We multiply parentheses

6n-(4(n-5)+2n)-20=0



We calculate terms in parentheses: -(4(n-5)+2n), so:

4(n-5)+2n

We add all the numbers together, and all the variables

2n+4(n-5)

We multiply parentheses

2n+4n-20

We add all the numbers together, and all the variables

6n-20

Back to the equation:

-(6n-20)



We get rid of parentheses

6n-6n+20-20=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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