2(3n-3)+28=40

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Solution for 2(3n-3)+28=40 equation: 



2(3n-3)+28=40

We move all terms to the left:

2(3n-3)+28-(40)=0

We add all the numbers together, and all the variables

2(3n-3)-12=0

We multiply parentheses

6n-6-12=0

We add all the numbers together, and all the variables

6n-18=0

We move all terms containing n to the left, all other terms to the right

6n=18

n=18/6

n=3

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