2(3n-3)+2=4(n+1)-2

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Solution for 2(3n-3)+2=4(n+1)-2 equation: 



2(3n-3)+2=4(n+1)-2

We move all terms to the left:

2(3n-3)+2-(4(n+1)-2)=0

We multiply parentheses

6n-(4(n+1)-2)-6+2=0



We calculate terms in parentheses: -(4(n+1)-2), so:

4(n+1)-2

We multiply parentheses

4n+4-2

We add all the numbers together, and all the variables

4n+2

Back to the equation:

-(4n+2)



We add all the numbers together, and all the variables

6n-(4n+2)-4=0

We get rid of parentheses

6n-4n-2-4=0

We add all the numbers together, and all the variables

2n-6=0

We move all terms containing n to the left, all other terms to the right

2n=6

n=6/2

n=3

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