2(3n-3)+2=4(n+1)-2

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Solution for 2(3n-3)+2=4(n+1)-2 equation:



2(3n-3)+2=4(n+1)-2
We move all terms to the left:
2(3n-3)+2-(4(n+1)-2)=0
We multiply parentheses
6n-(4(n+1)-2)-6+2=0
We calculate terms in parentheses: -(4(n+1)-2), so:
4(n+1)-2
We multiply parentheses
4n+4-2
We add all the numbers together, and all the variables
4n+2
Back to the equation:
-(4n+2)
We add all the numbers together, and all the variables
6n-(4n+2)-4=0
We get rid of parentheses
6n-4n-2-4=0
We add all the numbers together, and all the variables
2n-6=0
We move all terms containing n to the left, all other terms to the right
2n=6
n=6/2
n=3

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