2(3n-4)=(2n+3)+8

Solution for 2(3n-4)=(2n+3)+8 equation:

2(3n-4)=(2n+3)+8

We move all terms to the left:

2(3n-4)-((2n+3)+8)=0

We multiply parentheses

6n-((2n+3)+8)-8=0


We calculate terms in parentheses: -((2n+3)+8), so:

(2n+3)+8

We get rid of parentheses

2n+3+8

We add all the numbers together, and all the variables

2n+11

Back to the equation:

-(2n+11)


We get rid of parentheses

6n-2n-11-8=0

We add all the numbers together, and all the variables

4n-19=0

We move all terms containing n to the left, all other terms to the right

4n=19

n=19/4

n=4+3/4