2(3n-4)=n-2(1-2n)

Solution for 2(3n-4)=n-2(1-2n) equation:

2(3n-4)=n-2(1-2n)

We move all terms to the left:

2(3n-4)-(n-2(1-2n))=0

We add all the numbers together, and all the variables

2(3n-4)-(n-2(-2n+1))=0

We multiply parentheses

6n-(n-2(-2n+1))-8=0


We calculate terms in parentheses: -(n-2(-2n+1)), so:

n-2(-2n+1)

We multiply parentheses

n+4n-2

We add all the numbers together, and all the variables

5n-2

Back to the equation:

-(5n-2)


We get rid of parentheses

6n-5n+2-8=0

We add all the numbers together, and all the variables

n-6=0

We move all terms containing n to the left, all other terms to the right

n=6