2(3q+3)=6(3q+1)

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Solution for 2(3q+3)=6(3q+1) equation: 



2(3q+3)=6(3q+1)

We move all terms to the left:

2(3q+3)-(6(3q+1))=0

We multiply parentheses

6q-(6(3q+1))+6=0



We calculate terms in parentheses: -(6(3q+1)), so:

6(3q+1)

We multiply parentheses

18q+6

Back to the equation:

-(18q+6)



We get rid of parentheses

6q-18q-6+6=0

We add all the numbers together, and all the variables

-12q=0

q=0/-12

q=0

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