2(3q-10)=11(q-5)

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Solution for 2(3q-10)=11(q-5) equation: 



2(3q-10)=11(q-5)

We move all terms to the left:

2(3q-10)-(11(q-5))=0

We multiply parentheses

6q-(11(q-5))-20=0



We calculate terms in parentheses: -(11(q-5)), so:

11(q-5)

We multiply parentheses

11q-55

Back to the equation:

-(11q-55)



We get rid of parentheses

6q-11q+55-20=0

We add all the numbers together, and all the variables

-5q+35=0

We move all terms containing q to the left, all other terms to the right

-5q=-35

q=-35/-5

q=+7

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