2(3r+1)-2(5r+6)=4r+5-(6-r)

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Solution for 2(3r+1)-2(5r+6)=4r+5-(6-r) equation: 



2(3r+1)-2(5r+6)=4r+5-(6-r)

We move all terms to the left:

2(3r+1)-2(5r+6)-(4r+5-(6-r))=0

We add all the numbers together, and all the variables

2(3r+1)-2(5r+6)-(4r+5-(-1r+6))=0

We multiply parentheses

6r-10r-(4r+5-(-1r+6))+2-12=0



We calculate terms in parentheses: -(4r+5-(-1r+6)), so:

4r+5-(-1r+6)

determiningTheFunctionDomain
4r-(-1r+6)+5

We get rid of parentheses

4r+1r-6+5

We add all the numbers together, and all the variables

5r-1

Back to the equation:

-(5r-1)



We add all the numbers together, and all the variables

-4r-(5r-1)-10=0

We get rid of parentheses

-4r-5r+1-10=0

We add all the numbers together, and all the variables

-9r-9=0

We move all terms containing r to the left, all other terms to the right

-9r=9

r=9/-9

r=-1

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