2(3r+1)-4(r-4)=

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Solution for 2(3r+1)-4(r-4)= equation:


Simplifying
2(3r + 1) + -4(r + -4) = 0

Reorder the terms:
2(1 + 3r) + -4(r + -4) = 0
(1 * 2 + 3r * 2) + -4(r + -4) = 0
(2 + 6r) + -4(r + -4) = 0

Reorder the terms:
2 + 6r + -4(-4 + r) = 0
2 + 6r + (-4 * -4 + r * -4) = 0
2 + 6r + (16 + -4r) = 0

Reorder the terms:
2 + 16 + 6r + -4r = 0

Combine like terms: 2 + 16 = 18
18 + 6r + -4r = 0

Combine like terms: 6r + -4r = 2r
18 + 2r = 0

Solving
18 + 2r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + 2r = 0 + -18

Combine like terms: 18 + -18 = 0
0 + 2r = 0 + -18
2r = 0 + -18

Combine like terms: 0 + -18 = -18
2r = -18

Divide each side by '2'.
r = -9

Simplifying
r = -9

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