2(3r+10)=2r-20

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Solution for 2(3r+10)=2r-20 equation: 



2(3r+10)=2r-20

We move all terms to the left:

2(3r+10)-(2r-20)=0

We multiply parentheses

6r-(2r-20)+20=0

We get rid of parentheses

6r-2r+20+20=0

We add all the numbers together, and all the variables

4r+40=0

We move all terms containing r to the left, all other terms to the right

4r=-40

r=-40/4

r=-10

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