2(3r+4)-3(r+)=11

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Solution for 2(3r+4)-3(r+)=11 equation: 



2(3r+4)-3(r+)=11

We move all terms to the left:

2(3r+4)-3(r+)-(11)=0

We add all the numbers together, and all the variables

2(3r+4)-3(+r)-11=0

We multiply parentheses

6r-3r+8-11=0

We add all the numbers together, and all the variables

3r-3=0

We move all terms containing r to the left, all other terms to the right

3r=3

r=3/3

r=1

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