2(3r+4)-3(r+1)=14

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Solution for 2(3r+4)-3(r+1)=14 equation: 



2(3r+4)-3(r+1)=14

We move all terms to the left:

2(3r+4)-3(r+1)-(14)=0

We multiply parentheses

6r-3r+8-3-14=0

We add all the numbers together, and all the variables

3r-9=0

We move all terms containing r to the left, all other terms to the right

3r=9

r=9/3

r=3

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