2(3r+4)-3(r-1)=11

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Solution for 2(3r+4)-3(r-1)=11 equation: 



2(3r+4)-3(r-1)=11

We move all terms to the left:

2(3r+4)-3(r-1)-(11)=0

We multiply parentheses

6r-3r+8+3-11=0

We add all the numbers together, and all the variables

3r=0

r=0/3

r=0

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