2(3r+4)-3r(r+1)=11

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Solution for 2(3r+4)-3r(r+1)=11 equation: 



2(3r+4)-3r(r+1)=11

We move all terms to the left:

2(3r+4)-3r(r+1)-(11)=0

We multiply parentheses

-3r^2+6r-3r+8-11=0

We add all the numbers together, and all the variables

-3r^2+3r-3=0

a = -3; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-3)·(-3)
Δ = -27
Delta is less than zero, so there is no solution for the equation

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