2(3r-4)=7-4(r+3)

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Solution for 2(3r-4)=7-4(r+3) equation: 



2(3r-4)=7-4(r+3)

We move all terms to the left:

2(3r-4)-(7-4(r+3))=0

We multiply parentheses

6r-(7-4(r+3))-8=0



We calculate terms in parentheses: -(7-4(r+3)), so:

7-4(r+3)

determiningTheFunctionDomain
-4(r+3)+7

We multiply parentheses

-4r-12+7

We add all the numbers together, and all the variables

-4r-5

Back to the equation:

-(-4r-5)



We get rid of parentheses

6r+4r+5-8=0

We add all the numbers together, and all the variables

10r-3=0

We move all terms containing r to the left, all other terms to the right

10r=3

r=3/10

r=3/10

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