2(3s+1)=3(4-2s)

Solution for 2(3s+1)=3(4-2s) equation:

2(3s+1)=3(4-2s)

We move all terms to the left:

2(3s+1)-(3(4-2s))=0

We add all the numbers together, and all the variables

2(3s+1)-(3(-2s+4))=0

We multiply parentheses

6s-(3(-2s+4))+2=0


We calculate terms in parentheses: -(3(-2s+4)), so:

3(-2s+4)

We multiply parentheses

-6s+12

Back to the equation:

-(-6s+12)


We get rid of parentheses

6s+6s-12+2=0

We add all the numbers together, and all the variables

12s-10=0

We move all terms containing s to the left, all other terms to the right

12s=10

s=10/12

s=5/6