2(3s-3)-6=2(s+1)+6

Solution for 2(3s-3)-6=2(s+1)+6 equation:

2(3s-3)-6=2(s+1)+6

We move all terms to the left:

2(3s-3)-6-(2(s+1)+6)=0

We multiply parentheses

6s-(2(s+1)+6)-6-6=0


We calculate terms in parentheses: -(2(s+1)+6), so:

2(s+1)+6

We multiply parentheses

2s+2+6

We add all the numbers together, and all the variables

2s+8

Back to the equation:

-(2s+8)


We add all the numbers together, and all the variables

6s-(2s+8)-12=0

We get rid of parentheses

6s-2s-8-12=0

We add all the numbers together, and all the variables

4s-20=0

We move all terms containing s to the left, all other terms to the right

4s=20

s=20/4

s=5