2(3t+1)+-12=t-(t+9)

Solution for 2(3t+1)+-12=t-(t+9) equation:

2(3t+1)+-12=t-(t+9)

We move all terms to the left:

2(3t+1)+-12-(t-(t+9))=0

We add all the numbers together, and all the variables

2(3t+1)-(t-(t+9))=0

We multiply parentheses

6t-(t-(t+9))+2=0


We calculate terms in parentheses: -(t-(t+9)), so:

t-(t+9)

We get rid of parentheses

t-t-9

We add all the numbers together, and all the variables

-9

Back to the equation:

-(-9)


We add all the numbers together, and all the variables

6t+11=0

We move all terms containing t to the left, all other terms to the right

6t=-11

t=-11/6

t=-1+5/6