2(3t+1)-5=t-(t-2)

Solution for 2(3t+1)-5=t-(t-2) equation:

Simplifying
2(3t + 1) + -5 = t + -1(t + -2)

Reorder the terms:
2(1 + 3t) + -5 = t + -1(t + -2)
(1 * 2 + 3t * 2) + -5 = t + -1(t + -2)
(2 + 6t) + -5 = t + -1(t + -2)

Reorder the terms:
2 + -5 + 6t = t + -1(t + -2)

Combine like terms: 2 + -5 = -3
-3 + 6t = t + -1(t + -2)

Reorder the terms:
-3 + 6t = t + -1(-2 + t)
-3 + 6t = t + (-2 * -1 + t * -1)
-3 + 6t = t + (2 + -1t)

Reorder the terms:
-3 + 6t = 2 + t + -1t

Combine like terms: t + -1t = 0
-3 + 6t = 2 + 0
-3 + 6t = 2

Solving
-3 + 6t = 2

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 6t = 2 + 3

Combine like terms: -3 + 3 = 0
0 + 6t = 2 + 3
6t = 2 + 3

Combine like terms: 2 + 3 = 5
6t = 5

Divide each side by '6'.
t = 0.8333333333

Simplifying
t = 0.8333333333