2(3t+1)=4t+8

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Solution for 2(3t+1)=4t+8 equation: 



2(3t+1)=4t+8

We move all terms to the left:

2(3t+1)-(4t+8)=0

We multiply parentheses

6t-(4t+8)+2=0

We get rid of parentheses

6t-4t-8+2=0

We add all the numbers together, and all the variables

2t-6=0

We move all terms containing t to the left, all other terms to the right

2t=6

t=6/2

t=3

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