2(3t+1)=4t+8

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Solution for 2(3t+1)=4t+8 equation:



2(3t+1)=4t+8
We move all terms to the left:
2(3t+1)-(4t+8)=0
We multiply parentheses
6t-(4t+8)+2=0
We get rid of parentheses
6t-4t-8+2=0
We add all the numbers together, and all the variables
2t-6=0
We move all terms containing t to the left, all other terms to the right
2t=6
t=6/2
t=3

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