2(3t-2)=4(7t-1)

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Solution for 2(3t-2)=4(7t-1) equation: 



2(3t-2)=4(7t-1)

We move all terms to the left:

2(3t-2)-(4(7t-1))=0

We multiply parentheses

6t-(4(7t-1))-4=0



We calculate terms in parentheses: -(4(7t-1)), so:

4(7t-1)

We multiply parentheses

28t-4

Back to the equation:

-(28t-4)



We get rid of parentheses

6t-28t+4-4=0

We add all the numbers together, and all the variables

-22t=0

t=0/-22

t=0

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