2(3t-4)=17t+6

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Solution for 2(3t-4)=17t+6 equation: 



2(3t-4)=17t+6

We move all terms to the left:

2(3t-4)-(17t+6)=0

We multiply parentheses

6t-(17t+6)-8=0

We get rid of parentheses

6t-17t-6-8=0

We add all the numbers together, and all the variables

-11t-14=0

We move all terms containing t to the left, all other terms to the right

-11t=14

t=14/-11

t=-1+3/11

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