2(3t-4)=19t+6

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Solution for 2(3t-4)=19t+6 equation: 



2(3t-4)=19t+6

We move all terms to the left:

2(3t-4)-(19t+6)=0

We multiply parentheses

6t-(19t+6)-8=0

We get rid of parentheses

6t-19t-6-8=0

We add all the numbers together, and all the variables

-13t-14=0

We move all terms containing t to the left, all other terms to the right

-13t=14

t=14/-13

t=-1+1/13

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