2(3t-8)-41=10

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Solution for 2(3t-8)-41=10 equation: 



2(3t-8)-41=10

We move all terms to the left:

2(3t-8)-41-(10)=0

We add all the numbers together, and all the variables

2(3t-8)-51=0

We multiply parentheses

6t-16-51=0

We add all the numbers together, and all the variables

6t-67=0

We move all terms containing t to the left, all other terms to the right

6t=67

t=67/6

t=11+1/6

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