2(3u+3)+3u=5(u-4)+2

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Solution for 2(3u+3)+3u=5(u-4)+2 equation: 



2(3u+3)+3u=5(u-4)+2

We move all terms to the left:

2(3u+3)+3u-(5(u-4)+2)=0

We add all the numbers together, and all the variables

3u+2(3u+3)-(5(u-4)+2)=0

We multiply parentheses

3u+6u-(5(u-4)+2)+6=0



We calculate terms in parentheses: -(5(u-4)+2), so:

5(u-4)+2

We multiply parentheses

5u-20+2

We add all the numbers together, and all the variables

5u-18

Back to the equation:

-(5u-18)



We add all the numbers together, and all the variables

9u-(5u-18)+6=0

We get rid of parentheses

9u-5u+18+6=0

We add all the numbers together, and all the variables

4u+24=0

We move all terms containing u to the left, all other terms to the right

4u=-24

u=-24/4

u=-6

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