2(3u-1)+2=5-(2u-3)

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Solution for 2(3u-1)+2=5-(2u-3) equation: 



2(3u-1)+2=5-(2u-3)

We move all terms to the left:

2(3u-1)+2-(5-(2u-3))=0

We multiply parentheses

6u-(5-(2u-3))-2+2=0



We calculate terms in parentheses: -(5-(2u-3)), so:

5-(2u-3)

determiningTheFunctionDomain
-(2u-3)+5

We get rid of parentheses

-2u+3+5

We add all the numbers together, and all the variables

-2u+8

Back to the equation:

-(-2u+8)



We add all the numbers together, and all the variables

6u-(-2u+8)=0

We get rid of parentheses

6u+2u-8=0

We add all the numbers together, and all the variables

8u-8=0

We move all terms containing u to the left, all other terms to the right

8u=8

u=8/8

u=1

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